Question

If secθ + tan θ = p, then what is the value of secθ − tan θ ?

Answer 1

Given secA + tan A = p

$\small \bold{Recall \: the \: identity, \: sec^2A – tan^2A = 1}$

⇒ (secA + tan A)(secA – tanA) = 1

⇒ p × (secA – tanA) = 1

∴ (secA – tanA) = 1/p

Answer 2

Answer:

1/p

Step-by-step explanation:

Sec^2-tan^2=1

(Sec-tan).(sec+tan)=1

(Sec-tan).p=1

Sec-tan=1/p