Question

Q.6) Find the area of trapezium whose parallel side are 25 cm and 13 cm and other sides are 15 cm and 15 cm

Answer 1

Answer:

The area of trapezium:

260.3 cm²

Note:- The rest of your answer is in the second attachment.

Hope it helps

Please mark my answer as BRAINLIEST

Answer 2

GIVEN :

• Trapezium whose parallel side are 25 cm and 13 cm and other sides are 15 cm and 15 cm.

TO FIND :

• Area of trapazium = ?

SOLUTION :

In ∆ABC :-

• a = 15 cm
• b = 15 cm
• c = 15 cm

$\large{\boxed{\bf S = \dfrac{a + b + c}{2}}}$ ★

➨$\sf S = \dfrac{15 + 15 + 12}{2}$

➨$\sf S = \dfrac{42}{2}$

➨$\pink{\sf S = 21}$

Area of ∆ABC = $\sf \sqrt{s(s - a)\:(s - b)\:(s - c)}$

➨$\sf \sqrt{21(21 - 15)\:(21 - 15)\:(21 - 12)}$

➨$\sf 6 \times 3\sqrt{21}$

➨$\sf 18\sqrt{21}$

★ Area = 1/2 × base × height

➨ 18√21 = 1/2 × 12 × AF

➨ AF = 3√21

★ Area of parallelogram EDBA = B × h

➨ 13 × 3√21

➨ 39√21

★ Area of trapazium = Area of ∆ABC + Area of parallelogram EDBA

➨ 18√21 × 39√21

➨ 57√21

➨ 57 × 4.5

➨ 256.5 cm²

Therefore, area of trapazium is 256.5 cm².