If secθ-tanθ=X show that secθ=1/2(1/x+x)
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Answer:
Step-by-step explanation:
We realize that sec2 theta=1+tan2theta
So tan2theta= (x+1/4x)2-1
On explaining we get tan2theta=(x-1/4x)2
So tan theta =(x-1/4x) or - (x-1/4x)
At the point when tan theta =(x-1/4x),
sec theta +tan theta= x+1/4x+ x-1/4x=2x
at the point when tan theta =-(x-1/4x)
sec theta +tan theta= x+1/4x-x+1/4x=1/2x
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