Question

If secα+tanα=x then sec4α−tan4α−2secα⋅tanα is

Answer 1

Answer:

secα + tanα = p  ......(1) [ given]

We know that, sec²α-tan²α = 1

⇒ (secα + tanα)(secα-tanα) = 1

⇒  (secα-tanα) = 1/p ........... (2)

Adding (1) and (2)

⇒2 secα = p + 1/p

Subtracting (2) from (1)

⇒2tanα = p - 1/p   

Answer 2

Answer:

If secα + tanα = 2,

then the value of sinα is ( assume that 0 < α < 90°) a) 0.4 b) 0.5 c

) 0.6 d) 0.8. ... i)secα−tanα=12.....(ii)Adding equation (i ) ...