if sec theta = 5/3 and 0< theta <π/2. find all the T-ratios
Answers
Answer:
cos theta=3/5. (sec theta=1/cos theta)
sin^2theta=1-cos^2theta
1-9/25
16/25
sin theta=4/5
tan theta=sin theta/cos theta
4/5/3/5=4/3
cot theta=3/4. (1/tan theta)
cosec theta=5/4. (1/sin theta)
Answer:
When sec theta = 5/3, By Pythagoras theorem the remaining trigonometric ratios are listed below,
sin theta = opposite/hypotenuse = 4/5
cos theta = adjacent/hypotenuse = 3/5
tan theta = opposite/adjacent = 4/3
cosec theta = hypotenuse/opposite = 5/4
cot theta = adjacent/opposite = 3/4
Explanation:
Trigonometric Ratio:
- Based on the right angled triangle we have total 6 trigonometric ratios, which are given below
sin theta = opposite/hypotenuse
cos theta = adjacent/hypotenuse
tan theta = opposite/adjacent
cosec theta = hypotenuse/opposite
sec theta = hypotenuse/adjacent
cot theta = adjacent/opposite
- Given,
sec theta = 5/3 then
cos theta = 3/5 since {cos theta = 1/(sec theta)}
So, here adjacent value = 3, hypotenuse value = 5
- To find the value of adjacent, we apply Pythagoras theorem
By Pythagoras theorem,
Let opposite value = x
By Pythagoras theorem we can write,
Hence, opposite value = 4
By the values
adjacent value = 3, opposite value = 4, hypotenuse value = 5
Now all the trigonometric ratios can be written as
sin theta = opposite/hypotenuse = 4/5
cos theta = adjacent/hypotenuse = 3/5
tan theta = opposite/adjacent = 4/3
cosec theta = hypotenuse/opposite = 5/4
cot theta = adjacent/opposite = 3/4
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