Physics, asked by sam3710, 10 months ago

if sec theta = 5/3 and 0< theta <π/2. find all the T-ratios​

Answers

Answered by Mahijaan
19

Answer:

cos theta=3/5. (sec theta=1/cos theta)

sin^2theta=1-cos^2theta

1-9/25

16/25

sin theta=4/5

tan theta=sin theta/cos theta

4/5/3/5=4/3

cot theta=3/4. (1/tan theta)

cosec theta=5/4. (1/sin theta)


sam3710: thanks di
Answered by parulsehgal06
2

Answer:

When sec theta = 5/3, By Pythagoras theorem  the remaining  trigonometric ratios are listed below,

             sin theta = opposite/hypotenuse   = 4/5

            cos theta = adjacent/hypotenuse   = 3/5

             tan theta = opposite/adjacent        = 4/3

         cosec theta = hypotenuse/opposite  = 5/4

              cot theta = adjacent/opposite        = 3/4

Explanation:

Trigonometric Ratio:

  • Based on the right angled triangle we have total 6 trigonometric ratios, which are  given below

            sin theta = opposite/hypotenuse    

            cos theta = adjacent/hypotenuse  

             tan theta = opposite/adjacent      

         cosec theta = hypotenuse/opposite

             sec theta = hypotenuse/adjacent

              cot theta = adjacent/opposite  

  • Given,

              sec theta = 5/3   then

              cos theta = 3/5     since {cos theta = 1/(sec theta)}

           So, here adjacent value = 3, hypotenuse value = 5

  • To find the value of adjacent, we apply Pythagoras theorem

             By Pythagoras theorem,

                    (hypotenuse)^{2} = (opposite)^{2} +(adjacent)^{2}

                Let opposite value = x

             By Pythagoras theorem we can write,

                        5^{2}=x^{2}  +3^{2}

                        x^{2}=5^{2}-3^{2}

                        x=\sqrt{25-9}

                         x=\sqrt{16}

                         x=4

            Hence, opposite value = 4

       By the values

            adjacent value = 3, opposite value = 4, hypotenuse value = 5

       Now all the trigonometric ratios can be written as

             sin theta = opposite/hypotenuse   = 4/5

            cos theta = adjacent/hypotenuse   = 3/5

             tan theta = opposite/adjacent        = 4/3

         cosec theta = hypotenuse/opposite  = 5/4

              cot theta = adjacent/opposite        = 3/4

               

Learn more about  Trigonometry:

https://brainly.in/question/5488061?referrer=searchResults

                 

                           

                     

Similar questions