if sec theta = 5/4 , evaluate 1-tan theta/1+tan theta
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Answered by
83
sec@ =5/4
we know ,
sec@ =h/b =5/4
p=√(5^2-4^2)=3
now, tan@ =p/b =3/4
so, (1 - tan@)/(1 +tan@)
=>(1 -3/4)/(1+3/4)
=>(1/4)/(7/4)=1/7 (answer)
we know ,
sec@ =h/b =5/4
p=√(5^2-4^2)=3
now, tan@ =p/b =3/4
so, (1 - tan@)/(1 +tan@)
=>(1 -3/4)/(1+3/4)
=>(1/4)/(7/4)=1/7 (answer)
Answered by
65
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