If sec (theta +a) + sec (theta- a) = 2 sectheta and cos a # 1, then show that cos theta
= = 1/2 cos
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Answer:
sec(θ+α)+sec(θ−α)=2secθ
or
cos(θ+α)
1
+
cos(θ−α)
1
cosθ
2
or
cos(θ+α)cos(θ−α)
cos(θ−α)+cos(θ+α)
=
cosθ
2
or
cos
2
θ−sin
2
α
2cosθcosα
=
cosθ
2
or 2cos
2
θcosα=cos
2
θ−sin
2
α
or sin
2
α=cos
2
θ(1−cosα)
or 1−cos
2
α=cos
2
θ(1−cosα) or 1+cosα=cos
2
θ
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