If sec theta minus tan theta equal to x show that sec theta equal to one divided by x bracket x plus one divided by x bracket close and tan theta eqaul to one divided by x bracket one divided x minus x bracket close
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Answer:
Step-by-step explanation:
1/2(x+1/x)
=1/2[(sec theta-tan theta)+1/sec-tan]
1/2[ (sec-tan)+sec²-tan²/sec-tan]
1/2[sec-tan+(sec+tan)(sec-tan)/sec-tan]
1/2[2sec]
Sec
Same for RHS we get
tan theta
LHS
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