If sec theta.sin theta = 0 , then find the value of theta
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θ = nπ, where n = 0, ±1, ±2,..
Given:
secθ.sinθ = 0
To find:
The value of θ.
Solution:
secθ. sinθ = 0
=) (1/cosθ).sinθ = 0 ( secθ = 1/cosθ )
=) sinθ/cosθ = 0
=) tanθ = 0
tanθ is generally 0 at multiples of the 'π'.
Hence, θ=nπ where n= 0, ± 1, ±2,....
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