Question

if sec theta+ tan theta+1=0, then find the value of sec theta-tan theta.​

Answer 1

Answer:

sec a - tan a = (1/(sec a + tan a)) - 1

Step-by-step explanation:

let theta = a

sec a + tan a + sec^(2) a - tan^(2) a = 1

as sec^(2) a - tan^(2) a = 1

sec^(2) a - tan^(2) a = 1 - (sec a + tan a)

(sec a + tan a) × (sec a - tan a) = 1 - (sec a + tan a)

sec a - tan a = (1 - (sec a + tan a))/(sec a + tan a)

sec a - tan a = (1/(sec a + tan a)) - 1