Question

If sec theta - tan theta = 1/√3, then find the values of sec theta and tan theta. [You can use "x" in place of theta]

Answer 1

⭐⭐⭐⭐⭐ ANSWER ⭐⭐⭐⭐⭐

sec x - tan x = 1/√3

sec²x-tan²x = 1

=> (sec x + tan x) (sec x - tan x) = 1

=> (sec x + tan x) (1/√3) = 1

=> sec x + tan x = √3

So, Following elimination method,

sec x - tan x = 1/√3
sec x + tan x = √3

=> 2 sec x = 4/√3
=> sec x = 2/√3 [ANSWER]

Also, sec x + tan x = √3
=> tan x = √3 - 2/√3
=> tan x = 1/√3 [ANSWER]

⭐⭐⭐ ALWAYS BE BRAINLY ⭐⭐⭐

Answer 2

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