if sec theta + tan theta = 4/3 find sec theta × tan theta
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sec+ tan = 4/3
As sec^2 - tan^2 = 1
( sec+ tan) ( sec - tan) = 1
sec - tan = 3/4
Add both
2 sec = 4/3 + 3/4 = 16 + 9)/ 12 = 25/12
sec = 25/24
subtract both
2tan = 4/3 - 3/4 = 16 - 9)/ 12 = 7/12
tan = 7/24
Sec tan = 25/24 × 7/24 = 175/576
As sec^2 - tan^2 = 1
( sec+ tan) ( sec - tan) = 1
sec - tan = 3/4
Add both
2 sec = 4/3 + 3/4 = 16 + 9)/ 12 = 25/12
sec = 25/24
subtract both
2tan = 4/3 - 3/4 = 16 - 9)/ 12 = 7/12
tan = 7/24
Sec tan = 25/24 × 7/24 = 175/576
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