If sec theta - tan theta = 4 find cosec theta
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sec Ф-tanФ=4
we know that, sec^2 Ф-tan^2Ф= 1
(secФ-tanФ)(secФ+tanФ)=1 (∵a^2 - b^2 = (a+b)(a-b))
secФ - tanФ = 1/secФ+tanФ
since,
sec Ф-tanФ=4 ............i
∴sec Ф + tanФ=1/4..............ii
Add equation i and ii
2secФ = 4 +1/4
= 17/4
secФ = 17/8
tanФ = -15/8
1/cosФ - sinФ/cosФ = 4
17/8(1-sinФ) = 4
1-sinФ = 4*8/17
sinФ = 1-32/17
= 17-32/17
= -15/17
∴cosecФ = 1/sinФ = -17/15
Hope it helps...
Plz mark it the BRAINLIEST.
we know that, sec^2 Ф-tan^2Ф= 1
(secФ-tanФ)(secФ+tanФ)=1 (∵a^2 - b^2 = (a+b)(a-b))
secФ - tanФ = 1/secФ+tanФ
since,
sec Ф-tanФ=4 ............i
∴sec Ф + tanФ=1/4..............ii
Add equation i and ii
2secФ = 4 +1/4
= 17/4
secФ = 17/8
tanФ = -15/8
1/cosФ - sinФ/cosФ = 4
17/8(1-sinФ) = 4
1-sinФ = 4*8/17
sinФ = 1-32/17
= 17-32/17
= -15/17
∴cosecФ = 1/sinФ = -17/15
Hope it helps...
Plz mark it the BRAINLIEST.
percyjackson1:
my answer is easier to understand....:)
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