if sec theta + tan theta equals to 4 then value of cos theta will be
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1/cos ¢+sin¢+cos¢=4
=(1+sin¢)=4cos¢
Squaring on both side
(1)^2 +sin^2 +2sin¢=16
1+sin¢^2 +2sin¢-16=0
sin¢^2 +5sin¢-3sin¢+15
By this process you can find this
=(1+sin¢)=4cos¢
Squaring on both side
(1)^2 +sin^2 +2sin¢=16
1+sin¢^2 +2sin¢-16=0
sin¢^2 +5sin¢-3sin¢+15
By this process you can find this
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