if sec theta + tan theta is equal to P then find sin theta + cos theta in terms of p
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secA + tanA = p ...(i)
we know that sec2A - tan2A = 1
therefore (secA - tanA)(secA + tanA) = 1
so secA - tanA = 1/p ....(ii)
adding (i) and (ii) we get
secA = p2+1/2p
similarly we find tanA and sinA
we know that sec2A - tan2A = 1
therefore (secA - tanA)(secA + tanA) = 1
so secA - tanA = 1/p ....(ii)
adding (i) and (ii) we get
secA = p2+1/2p
similarly we find tanA and sinA
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