Math, asked by Noborup, 1 year ago

Please give me its answer within 2 minutes

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Answered by AmanNsw
1
Answes 18
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Answered by ShuchiRecites
1
\textbf{ \underline{ Hello Mate! }}

x = 2 -  \sqrt{5}  \\  \frac{1}{x}  =  \frac{1}{2 -  \sqrt{5} }  \\ rationalize \\  \frac{1}{2 -  \sqrt{5} }  \times  \frac{2 +  \sqrt{5} }{2 +  \sqrt{5} }  \\  =  \frac{2 +  \sqrt{5} }{ {2}^{2} -  { \sqrt{5} }^{2}  }  =  \frac{2 +  \sqrt{5} }{4 - 5}  \\  =  \frac{2 +  \sqrt{5} }{ - 1}  \: or \:  - 2 -  \sqrt{5}  \\  {x }^{2}   =  {(2 -  \sqrt{5} )}^{2}  \\  = 4 + 5 - 4 \sqrt{5}  = 9 - 4 \sqrt{5}  \\  {( \frac{1}{x}) }^{2}  =   {( - 2 -  \sqrt{5}) }^{2}   \\  = 4 + 5 - 2 \times ( - 2) \times ( \sqrt{5} ) \\  = 9 + 4 \sqrt{5}  \\  {x}^{2}   +  {( \frac{1}{x} )}^{2}  =  \\ =  9 - 4 \sqrt{5}  + 9 + 4 \sqrt{5}  \\  = 18
\boxed{ Hence\:answer\:is\:18 }

Have great future ahead!

ShuchiRecites: Thanks for attempting brsinliest
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