Question

If sec theta + tan theta = m , show that m square - 1 / m square + 1 = sin theta

Answer 1

m^2-(1/m)^2+1=(sec theta + tan theta)^2-(1/sec theta + tan theta)^2 + 1 =( sec^2 theta + tan^2 theta + 2 sec theta×tan theta) - (1/sec^2theta+tan^2 theta+2 sec theta×tan theta) + 1 .