Question

if sec theta + tan theta =p then sec theta- tan theta =1/P true or false​

Answer 1

Answer:

True

Step-by-step explanation:

Sec^2 theta - Tan^2 theta =1

=>(Sec theta+tan theta)(sec theta-tan theta)=1

=>p*(sec theta-tan theta)=1

=>Sec theta - Tan theta =1/p

Answer 2

Answer:

True

Step-by-step explanation:

${ \sec( \alpha ) }^{2} - { \tan( \alpha ) }^{2} = 1$

(sec(a) +tan(a))*(sec(a)-tan(a))=1

since ,sec theta +tan theta =p

thus sec theta -tan theta=1/p.