If sec theta + tan theta = x , then sec theta = ?
(a) (x^2 + 1)/x (c)(x^2 - 1)/2x
(b)(x^2 + 1)/2x (d)(x^2 - 1)/x
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sec² A = (x - tan A)²
sec² A = x² + tan² A - 2x tan A
sec² A- tan²A= x²-2xtanA
1= x²- 2 x tan A
1-x²= - 2x tan A
tan A= x²- 1/2x
Given
sec A + tan A = x
sec A + x²-1/2x=x
sec A = x- (x²-1/2x)
sec A = 2x²-x²+1/2x
sec A = x²+1/2x
Option B is correct
sec² A = x² + tan² A - 2x tan A
sec² A- tan²A= x²-2xtanA
1= x²- 2 x tan A
1-x²= - 2x tan A
tan A= x²- 1/2x
Given
sec A + tan A = x
sec A + x²-1/2x=x
sec A = x- (x²-1/2x)
sec A = 2x²-x²+1/2x
sec A = x²+1/2x
Option B is correct
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