what is the volume occupied by 16 gram of oxygen under N.T.P conditions? please help me tomorrow is my exam
Answers
Answered by
21
the answer to your question is 11.20 litres
sanjaycharanr:
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Answered by
58
as the volume occupied by 1mole of any gas under NTP is 22.4 L
and 1 mole of O2=32 g
so 16g=0.5 mole
hence 0.5mole of O2 will occupy 22.4/2 L of volume
i.e., 11.2 L.
and 1 mole of O2=32 g
so 16g=0.5 mole
hence 0.5mole of O2 will occupy 22.4/2 L of volume
i.e., 11.2 L.
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