Question

if sec thita= ×+¼×, then the value of sec thita+ tan thita​

Answer 1

Answer:

2x

Step-by-step explanation:

Given,

secØ = x+1/4x

sec²Ø = (x+1/4x)²

1+tan²Ø = x²+1/16x²+1/2

tan²Ø = x²+1/16x²-1/2 = x²+1/16x²-2.x.1/4x

tan²Ø = (x-1/4x)²

tanØ = x-1/4x

Now,

secØ+tanØ = x+1/4x + x-1/4x = 2x.