if sec x sin× =0 then find the value of x
Answers
Answered by
3
x=0;
secx=1/cosx;
sinx/cosx=tanx;
tanx=0;
x=0
secx=1/cosx;
sinx/cosx=tanx;
tanx=0;
x=0
Answered by
4
sec x sin x=0
(1/cos x)(√1-cos²x)=0
√1-cos²x=0⇒1-cos²x=0⇒1=cos²x⇒cos x=√1=1=cos 0°
⇒x=0°
∴x=0°
(1/cos x)(√1-cos²x)=0
√1-cos²x=0⇒1-cos²x=0⇒1=cos²x⇒cos x=√1=1=cos 0°
⇒x=0°
∴x=0°
Similar questions