Question

if sec x.sin(36+x)=1,find value of x so that angles (36+x) and x are acute angles

Answer 1

Answer:

the angle is 54 degree and the value of x is also

Answer 2

Answer:

x = 27

Step-by-step explanation:

The given equation is secx * sin(36+ x) = 1

Move secx to right hand side, it will become

=> sin(36 + x) = (1/secx)

[1/sec∅ = cos∅]

=> sin(36 + x) = cosx

=> sin(36 + x) = sin(90 - x)

=> 36 + x = 90 - x

=> 2x = 54

=> x = 27

Hence, the value of x = 27.

Acute angle = Angle which is less than 90°.

Now, we find (36 + x) value.

=> 36 + 27

=> 63(It is acute)

and x = 27 is also acute.

Hence, (36 + x) and x are acute angles.

#Hope my answer helped you!