If Sec0+tan0=P then Sec 0=?
Answers
Answered by
1
Step-by-step explanation:
sec^2 θ- tan^2 θ= 1 [formula ]
(sec θ-tan θ) (sec θ+tan θ) = 1 [by factorising]
(sec θ-tan θ) p = 1
sec θ-tan θ = 1/p--------eq-2
sec θ+tan θ=p----------eq-1
Now, by using elimination method
sec θ =1-(p) ^2/2p
or 1/2p - p/2
please mark it as brainliest :-)
Similar questions