Question

If sec2A = cosec(A - 27°) where 2A is an acute angle. Then the measure of ∠A is

Answer 1

Answer:

39

Step-by-step explanation:

sin(A-27) = cos 2A

sin(A-27) = sin (90 -2A) since 2A is acute

A-27 = 90 -2A

A=39

Answer 2

Answer:

Angle A is 39°.

Step-by-step explanation:

Given that,

Sec2A=cosec(A-27°)

=> cosec(90°-2A)=cosec(A-27°)

{cosec(90°-A)=secA}

Comparing angle,

=> 90°- 2A = A - 27°

=> 90° + 27° = A + 2A

=> 117 = 3A

=> A = 117/3

=> A = 39°

Hence, Angle A is 39°. 2A is an acute angle...