If secA= 12/5 then cosecA= ?
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if sec a is 12/5 then
cos a would be 5/12 that means base/hypothenuse = 5/12
if we will form a right triangle according to the given
we will get 5^2+p^2=12^2(by Pythagoras theorem)
where p is the perpendicular
p^2= 144-25
p=√119
as coseca = h/p
codec a = 12/√119
hope this is correct.
cos a would be 5/12 that means base/hypothenuse = 5/12
if we will form a right triangle according to the given
we will get 5^2+p^2=12^2(by Pythagoras theorem)
where p is the perpendicular
p^2= 144-25
p=√119
as coseca = h/p
codec a = 12/√119
hope this is correct.
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