The sides of a right triangle measure 6 cm, 8 cm and 10 cm. Find the volume of the rotation cone and the area of the growth on the side of that triangle 8 cm long. (pi = 3.14)
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When a right triangle with sides 6 cm, 8 cm and 10 cm is rotated about the side 8 cm, then solid formed is a cone whose height of a cone, h = 8 cm and radius of a cone, r = 6 cm. Slant height of a cone, l = 10 cm
Volume of a cone = 1/3 πr2h = (1/3) x (22/7) x 6 x 6 x 8
⇒ 6336/21 = 301.7 cm3
and curved surface of the area of cone = πrl
⇒ (22/7) x 6 x 10 = 1320/7 = 188.5 cm2
Hence, the volume and surface area of a cone are 301.7 cm3 and 188.5 cm2, respectively
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I don't want to write too much just for 5pts
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