If secA= 25/7 then find tanA= ?
sairam22082003:
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Step-by-step explanation:
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Step-by-step explanation:
Let thita = #
Sec# = 25/7
Tan# = ?
But, tan# = sin#/ cos#
And,. Cos# = 1/ sec#
=1/25/7
=7/25
Sin# =^1-cos2#.........^ = root
=1-7/25
=25-7/25
=18/25
:: tan# = 18/25/7/25
=18/25×25/7
25,25 cut
Tan# = 18/7.......
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