Question

if secA=5/3 ,then find the other trignometric ratios for AngleA
step by step explanation​

Answer 1

Answer:

$\sec(a) = \frac{5}{3} = \frac{h}{p}$

$by \: phythagours \: therom$

${h}^{2} = {p}^{2} + {b}^{2}$

${b}^{2} = {h}^{2} - {p}^{2}$

${b}^{2} = {5}^{2} - {3}^{2}$

${b}^{2} = \: 25 - 9$

${b}^{2} = 16$

$b = 4$

$\sin(a) = \frac{p}{h} = \frac{3}{5}$

$\cos(a) = \frac{b}{h} = \frac{4}{5}$

$\tan(a) = \frac{p}{b} = \frac{3}{4}$

$\cot(a) = \frac{b}{p} = \frac{4}{3}$

$\csc(a) = \frac{h}{b} = \frac{5}{4}$

Answer 2

hope it helps you my first id