Question

if secA= 5/4
then what is 1-tanA/1+tanA

Answer 1

Answer:

$\huge\underline{ \underline{ \red{your \: \: answer}}}$

Step-by-step explanation:

$\sf\red{ sec A= \frac{5}{4} } \\ \sf\red{ = > {sec}^{2} A = \frac{25}{16} } \\ \sf\red{ = > 1 + {tan}^{2} A= \frac{25}{16} } \\ \sf\red{ = > {tan}^{2} A = \frac{25}{16} - 1} \\ \sf\red{ = > {tan}^{2} A = \frac{25 - 16}{16} } \\ \sf\red{ = > {tan}^{2} A = \frac{9}{16} } \\ \sf\red{ = > tan A = \sqrt{ \frac{9}{16} } } \\ \sf\red{ = > tan A= \frac{3}{4} } \\ \sf\purple{ \frac{1 - tan A}{1 + tanA } = ?} \\ \sf\purple{ = > \frac{1 - \frac{3}{4} }{1 + \frac{3}{4} } } \\ \sf\purple{ = > \frac{ \frac{4 - 3}{4} }{ \frac{4 + 3}{4} } } \\ \sf\purple{ = > \frac{ \frac{1}{4} }{ \frac{7}{4} } } \\ \sf\purple{ = > \frac{1}{4} \times \frac{4}{7} } \\ \sf\purple{ = > \frac{1}{7} }$

$\large\boxed{ \fcolorbox{pink}{yellow}{hope \: it \: help \: you}}$

Answer 2

Answer:

Step-by-step explanation: