Math, asked by mongvohien, 9 months ago

Three cyclists cycle along identical circular tracks, which are exactly one third of a kilometre in circumference. Three tracks meet in the centre as show in the attached picture. Each cyclist rides around a different circle. One cyclist travels at 6 km/h, another at 9 km/h, and the third at 12 km/h.

Answers

Answered by amitnrw
1

Given: Three cyclists cycle along identical circular tracks, which are exactly one third of a kilometre in circumference.  One cyclist travels at 6 km/h, another at 9 km/h, and the third at 12 km/h.

To find : Time after which they will meet at starting point

Solution:

Circumference = 1/3 km

Speed of 1st = 6k/hr

Time after which 1st reach at staring point  =  (1/3)/6   = 1/18 hr

Speed of 2nd = 9 km/hr

Time after which 2nd reach at staring point  =  (1/3)/9   = 1/27 hr

Speed of 3rd= 12 k/hr

Time after which 1st reach at staring point  =  (1/3)/12   = 1/36 hr

To find time after which they will meet at starting point

we need to find LCM of

1/18  , 1/27  , 1/36

= 6/108 , 4/108  , 3/108

LCM of 6, 4 & 3

6 = 2 * 3

4 = 2 * 2

3  = 3

LCM = 2 * 2 * 3 = 12

LCM of 6/108 , 4/108  , 3/108    = 12/108 = 1/9

LCM of 1/18  , 1/27  , 1/36 = 1/9

after 1 /9 hr they will meet at starting point

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Answered by simonprince0318
0

Answer:

Step-by-step explanation:

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