Question

if secA + tan A=k then secA-tanA=?

Answer 1

Solution :

Given secA + tanA = k ----( 1 )

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We know the Trigonometric identity:

sec²A - tan²A = 1

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=> sec²A - tan²A = 1

=> (secA+tanA)(secA-tanA) = 1

=> k(secA-tanA) = 1 [ from ( 1 )]

=> SecA - tanA= 1/k

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