If secA+tanA=m and secA-tanA=n,find the value of-/mn
AR17:
we have to find mn??
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the value of √mn = 1
explanation:
√mn= √{(secA+tanA)(secA-tanA)}
=√{(secA)^2 - (tanA)^2}
=√1 ; <as (secA)^2 - (tanA)^2 = 1>
= 1
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I hope this helps you...
explanation:
√mn= √{(secA+tanA)(secA-tanA)}
=√{(secA)^2 - (tanA)^2}
=√1 ; <as (secA)^2 - (tanA)^2 = 1>
= 1
____________________________
I hope this helps you...
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