Question

three vertices of a rectangle are (3,2) (-4,2) and (-4,5) plot there points and find the quadnates of the fouth vertex

Answer 1

Let A,B,C and D be vertices of rectangle
Midpoint of diagonal AC=Midpoint of diagonal BD
x1+x2/2,y1+y2/2=x1+x2/2,y1+y2/2
Let A,B and C be(3,2) (-4,2) and (-4,5),then
3+(-4)/2,2+5/2=-4+x2/2,2+y2/2
By equating x and y coordinates we get
3+(-4)/2=-4+x2/2. 2+5/2=2+y2/2
-1=-4+x2. 7=2+y2
x2=-4+1=-3. y2=7-2=5
Therefore fourth vertex is (x2,y2)=(-3,5)
HOPE IT WAS HELPFUL