Question

If secx + cosx = 98, then find out tan^2x – sin^2x is?

Answer 1

Step-by-step explanation:

1/cosx + cosx = 98

cosx^2 +1 -98 cosx = 0

98×98 - 4 × 1×1

solve forward and find value of cos

then to find value of sinx

sin^2x = 1-cos^2x

and sinx/cosx = tanx