Question

a number has two digit whose sum is 9.if 37 is subtrated from it .its digits are interchanged find the number​

Answer 1

Answer:

The Required no. is 63 !!

Explanation:

Let ones digit be y and tens digit be x then the no. would be 10x + y ( because it is given that the no. is of two digit )

Given :- a number has two digit whose sum is 9

i.e, x + y = 9 --- ( i )

And ,

also, if 37 is subtrated from it it's digit are interchange!!

i.e,

the interchange no. would be then

10y + x

10x + y - 37 = 10y + x

9x -9y = 37 -- ( ii )

[ Refer to the attachment ]

Hence , we get x = 6 and y = 3

So, the no. is 10x + y = 10 ( 6 ) + 3 = 63