If seven time of 7th term of an A.P is equal to the 11 times of 11th term of it, then find the
18th term of that A.P
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7(a+6d) = 11(a+10d)
7a+42d = 11a + 110d
-4a=110d-42d
-4a=68d
a=-17d
therefore 18th term of an Ap is
a+17d= -17d+17d
=0
hence answer =0
7a+42d = 11a + 110d
-4a=110d-42d
-4a=68d
a=-17d
therefore 18th term of an Ap is
a+17d= -17d+17d
=0
hence answer =0
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