If seventh term of AP is 40. Find the sum of first 13 terms?
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Answer:
520
Step-by-step explanation:
Seventh term = 40
=> a(7) = 40
=> a + ( 7 - 1 )d = 40
=> a + 6d = 40
Sum of 13 terms = S(13) = 13/2 × { 2a + ( 13 - 1 )d }
=> S(13) = 13/2 × ( 2a + 12d )
=> S(13) = 13/2 × { 2( a + 6d) }
=> S(13) = 13 × ( a + 6d)
=> S(13) = 13 × 40
=> S(13) = 520
Therefore sum of first 13 terms is 520.
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