Question

If side of a cuboid is increased by 50% the its surface area

Answer 1

Let the edge = a cm   

So increase by 50 % = a + a/2 = 3a/2  

Total surface Area of original cube = 6a26a2  

TSA of new cube = 6(3a2)263a22 =6(9a24)69a24=  13.5a213.5a2   

Increase in area = 13.5a2−6a213.5a2-6a2 =7.5a27.5a2  

 7.5a27.5a2 Increase % =7.5a26a2×1007.5a26a2×100 = 125%

Answer 2

Answer:

125%

Step-by-step explanation: