If sides of two similar triangles are in the rario 4:3then find the ratio of their areas
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By theorem 6.6,
The ratio of the areas of similar triangles is equal to the square of the distance between them.
ar (ABC)/ar (PQR)=AB^2/PQ^2-----(1)
Let triangles ABC AND PQR
AB/PQ=4/3
AB^2/PQ^2=16/9
ar (ABC)/ar (PQR)=16/9
The area is divided in The ratio 16:9
BYE
By theorem 6.6,
The ratio of the areas of similar triangles is equal to the square of the distance between them.
ar (ABC)/ar (PQR)=AB^2/PQ^2-----(1)
Let triangles ABC AND PQR
AB/PQ=4/3
AB^2/PQ^2=16/9
ar (ABC)/ar (PQR)=16/9
The area is divided in The ratio 16:9
BYE
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Answer:
The ratio of the areas of similar triangles is equal to the square of the distance between them.
ar (ABC)/ar (PQR)=AB^2/PQ^2-----(1)
Let triangles ABC AND PQR
AB/PQ=4/3
AB^2/PQ^2=16/9
ar (ABC)/ar (PQR)=16/9
The area is divided in The ratio 16:9
Step-by-step explanation:
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