Question

If simple pendulum makes 30 oscillations in 5 seconds ,calculate its frequency and time period

Answer 1

time period=30/5=6 oscillations per second

Answer 2

The frequency and time period is 6 Hz and 0.17 s respectively.

Explanation:

Given that,

A simple pendulum makes 30 oscillations in 5 seconds. The frequency of pendulum is equal to the number of oscillations per unit time. It is given by :

$f=\dfrac{n}{t}\\\\f=\dfrac{30}{5\ s}\\\\f=6\ Hz$

Let T is the time period. We know that the reciprocal of time period is called frequency.

$T=\dfrac{1}{f}\\\\T=\dfrac{1}{6\ Hz}\\\\T=0.17\ s$

So, the frequency and time period is 6 Hz and 0.17 s respectively. Hence, this is the required solution.

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