if sin 0 = 3/5 , then find cot 0.
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Let, Perpendicular =AB =3k and Hypotenuse =AC =5k where, k is any positive integer So, by Pythagoras theorem, we can find the third side of a triangle ⇒ (AB)2 + (BC)2 = (AC)2 ⇒ (3k)2 + (BC)2 = (5k)2 ⇒ 9k2 + (BC)2 = 25k2 ⇒ (BC)2 = 25 k2 – 9 k2 ⇒ (BC)2 = 16 k2 ⇒ BC =√16 k2 ⇒ BC =±4k But side BC can’t be negative. So, BC = 4k Now, we have to find the value of cos θ and tan θ.
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