if sin 0+cos 0=route2, then evaluate tan0+cot0
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hello there !!!
i will be using A instead of 0
we have ,
sinA+cosA=√2
=> ( sinA+cosA)²=(√2 )² [squaring both the sides ]
=> sin²A+cos²A+2sinAcosA=2
=> 1+2sinAcosA =2 [since sin²A+cos²A=1]
=> sinAcosA=1/2 -------(1)
now ,
tanA+cotA
=>sinA/cosA+cosA/sinA
=> sin²A+cos²A/sinAcosA [taking LCM]
=> 1/sinAcosA
=> 1/1/2 [using 1]
=> 2
i will be using A instead of 0
we have ,
sinA+cosA=√2
=> ( sinA+cosA)²=(√2 )² [squaring both the sides ]
=> sin²A+cos²A+2sinAcosA=2
=> 1+2sinAcosA =2 [since sin²A+cos²A=1]
=> sinAcosA=1/2 -------(1)
now ,
tanA+cotA
=>sinA/cosA+cosA/sinA
=> sin²A+cos²A/sinAcosA [taking LCM]
=> 1/sinAcosA
=> 1/1/2 [using 1]
=> 2
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