Question

If Sinθ = 1/3, then 2Cosec²θ+ cot²θ - 1 = _______.
A] 15 b] 25 c] 50 d] 45

Answer 1

Answer:

25

Step-by-step explanation:

Answer 2

Let the theta be O
SinO = 1/3
CosecO=3
=3x/x
(3x)^2 - x^2 = 9x^2 -x^2=8x^2
Square root = 2 (root2) x
CotO=2root2

2Cosec^2 O + cot^2 0 -1
2(3)^2 + (2root2)^2 -1
= 18+ 8 -1
=26