If sin θ 1 , + sin θ 2 , + sin θ 3 = 3 , 0° θ 1 , θ 2 θ ≤ 90°, then cos θ 1 , + cos θ 2 , + cos θ 3 is _____
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SIN THETA 1 +SIN THETA 2+SIN THETA 3 =3
THIS CAN ONLY BE POSSIBLE WHEN ALL THE THETA WILL BE 90 DEGREE(90 DEGREE1)
SO 3 COS 90= 0
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