If sin⁻¹ x + sin⁻¹ y = 2 , then the value of cos⁻¹ x + cos⁻¹ y is _
(a) 2π/3 (b) π/3 (c) π/2 (d) π
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Explanation:
If sin⁻¹ x - cos⁻¹ x = π/6...eq1
, then to find the value x,we must convert the entire equation into one inverse triginomertic function,by using formula's of inverse triginomertry.
As we know that
sin⁻¹ x + cos⁻¹ x =π/2
so sin⁻¹ x =π/2-cos⁻¹ x
put this value to sin⁻¹ x into eq1
π/2-cos⁻¹ x-cos⁻¹ x=π/6
-2cos⁻¹ x =π/6-π/2
2cos⁻¹ x=2π/6
cos⁻¹ x=π/6
take cos both sides
cos(cos⁻¹ x)=cos(π/6)
x=√3/2
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