if sin 2 theta =cos(theta-36°), 2theta and theta - 26° are acute angles then find the value of theta
Answers
Answered by
10
Hey friend
Here is your answer
Sin2@=Cos(@-36°)
[•USING cos(90-@)=sin@]
Cos(90°-2@)=Cos(@-36)
90-2@=@-36
3@=90+36
3@=126
@=126/3
@=42
Hope this helps you
Here is your answer
Sin2@=Cos(@-36°)
[•USING cos(90-@)=sin@]
Cos(90°-2@)=Cos(@-36)
90-2@=@-36
3@=90+36
3@=126
@=126/3
@=42
Hope this helps you
Answered by
3
Given:
-
and
are acute angles.
To Find:
- The value of
Solution:
⇒
Using formula
We get,
⇒
⇒
⇒
⇒
⇒
⇒
Thus, the value of
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