Question

if sin 3 A=cos(A-6(,where 3 A is an acute angle,find the value of A

Answer 1

Answer:

cos (90-A)=sinA

given sin A=cosA

cos (90-A)=CosA

90=2A

A=45

Answer 2

Answer:

24

Step-by-step explanation:

question

sin 3 A=cos(A-6) find A

given

A is acute

to find

A

Formulas required

cosA = sin(90-A)

solution

sin3A = cos(A-6)          given

sin3A = sin(90-(A-6))      using formula

therfore 3A =90-(A-6)

===> 4A = 96

===> A = 24

therfore A is 24