Question

If sin 3 θ = cos (θ − 6°), where 3 θ and θ − 6° are acute angles, find the value of θ.

Answer 1

SOLUTION :  

Given : sin 3θ = cos(θ −6°) and 3θ and  θ −6° are acute angles.

sin 3θ = cos(θ −6°)  

= cos(90° -  3θ) = cos(θ − 6°)

[cos (90 - θ) = sin θ]

On equating both sides,

90°– 3θ = θ – 6°

−3θ − θ = - 6°−90°

− 4θ = - 96°

4θ = 96°

θ = 96°/4

θ = 24°

Hence, the value of A is 24° .

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Answer 2

the value of A= 24......