If sin θ = √3 cos θ, then find the values of cos θ and sin θ.
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Answered by
0
Answer:
since we know that ,
sin² theta + cos² theta= 1
therefore+√3cos theta) ²+cos² theta=1
3cos²theta+cos² theta=1
4cos² theta=1
cos²theta=1/4
cos theta=1/2
therefore sin² theta + cos² theta=1
sin²theta+(1/2) ²=1
sin² theta+1/4=1
sin² theta=1-1/4
sin² theta=3/4
sin theta=√3/2
Answered by
1
√3 sin θ = cos θ
cos θ / sin θ = √3
cot θ = √3
cot θ = cot 30°
θ = 30°
then ,
- sin 30° = ½
- cos 30° = 1/√2
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